If a ball is thrown in the air with a velocity 48 ft/s, its height in feet t seconds later is given by y = 48t − 16t2. find the average velocity for the time period beginning when t = 2 and lasting. a. 0.5 second b. 0.1 second c. 0.05 second d. 0.01 second.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

answer: 34rtyj,jkhtyetwrhyjeuiejnbhdfknbkguxfrbhkfdbjvkmbd,kvbsd.kxjvbhjnfbgjxdfn

step-by-step explanation: