What does pythagoras’ famous theorem involve?

✴ It states that the Hypotenuse² is equals to Perpendicular² + Base².

In other words, The square of Hypotenuse or side opposite to 90° is equals to the sum of its Perpendicular & Base sq, where Hypotaneous is largest side.

Where,

We have to draw QD ⊥ PR ,

In △PDQ and △PQR , we have

∠P = ∠P ( common ) .

∠PDQ = ∠PQR [ each equal to 90° ] .

∴ △PDQ ∼ △PQR [ By AA-similarity ] .

PD/PQ = PQ/PR .

PQ² = PD × PR ----------(1) .

In △QDR and △PQR , we have

∠R = ∠R ( common ) .

∠QDR = ∠PQR [ each equal to 90° ] .

∴ △QDR ∼ △PQR [ By AA-similarity ] .

DR/QR = QR/PR .

QR² = DR × PR ----------(2) .

Taking sum of 1 & 2 equation,

PQ² + QR² = PD × PR + DR × PR .

PQ² + QR² = PR( PD + DR ) .

PQ² + QR² = PR × PR

PQ² + QR² = PR²

PR² = PQ² + QR²

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the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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