The length of a rectangular room is 6 feet longer than twice the width. if the rooms perimeter is 180 what are the rooms dimensions

P= 2L+2W
180= 2(6+2w)+ 2w
Solve this and get W
And to find the Length, L would be 6+2w so plug in what ever you get for W into this to find L

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!