2.solve the system using substitution.
2x+2y=38
y=x+3
a. (8,11)
b. (4,7)
c. (35/4, 47/4)
d. (-4,-7)

2x+2y=38
y=x+3

First you would substitute the y for x+3
2x+2(x+3)=38

You would multiply the 2 by the x+3
2x+2x+6=38

Add the 2x and the 2x
4x+6=38

Subtract the 6 on both sides
4x=32

Divide the 4 on both sides
x=8

Now substitute the x in the second problum for 8
y=8+3

Add the 8 and the 3 to solve for y
y=11

Your answers
x=8
y=11
the correct answer would be A:(8,11)