Find the area of a 9-inch by 6-inch rectangle with a 4-inch by 4-inch square removed from one corner.

38 square inches

Step-by-step explanation:

Given: A 9-inch by 6-inch rectangle with a 4-inch by 4-inch square removed from one corner.

To find: Area of the remaining portion.

Solution:

In order to find the area of the remaining portion, we first need to find the area of rectangle, and area of square, then we need to subtract the area of square from area of rectangle.

We have, the dimension of rectangle as 9-inch by 6-inch

So area of rectangle square inches

We have dimension of square as 4 inch.

So, area of square square inches

Now, area of remaining portion

area of remaining portion square inches

Hence, area of remaining portion is 38 square inches.

1.true 2.false? ? i think. .

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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