What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)?

The equation for the given line is y − 1 = 4(x + 3). Let us convert this equation in slope intercept form y= mx +b, where m is slope and b is the y-intercept. Thus, the slope of this line is 4.Now, we know that the slope of parallel lines are equal. Hence, the slope of the required line is same as the slope of the given line. Hence, the slope of the required line is m = 4It passes through the point (4,32).The point slope form of a line is given by Therefore the equation of the line is y = 4x+16,D is the correct option.