The slope of a line is -4, and the y-intercept is -3. what is the equation of the line written in slope-intercept form? y = -4x - 3 y = -4x + 3 y = 4x - 3

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Multiplying an even number of negative numbers gives an answer that is choose from:

What is the missing step in this proof ?