Aplane , parallel to the base of a cone intersects the cone at the midpoint between points a and b. determine the area of the cross section formed by the intersection of the plane and the cone . leave the answers in terms of pi.

a) 1.5pi in^2
b) 3 pi in ^2
c) 9 pi in^2
d) 36 pi in ^2

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

it would rotate about 180 degrees.

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