Mathematics, 03.01.2020 15:31 Arealbot
Suppose that f(pi/3)=4 and f'(pi/3)=-2 let g(x)=f(x)sinx and h(x)=cosx/f(x). find g'(pi/3) and h'(pi/3)
Answers: 3
and 
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![\to \bold{h'(x) = \frac{[- \sin(x)\times f(x) +f'(x)\times cos(x)]}{[f(x)]^2}}\\\\](/tpl/images/0441/3877/340bb.png)
![\to h'(\frac{pi}{3}) = [(-\frac{\sqrt{3}}{2})\times 4 + \frac{(-2)\times (\frac{1}{2})]}{[4]^2}\\\\\to h'(\frac{pi}{3}) = \frac{[-\frac{\sqrt{3}}{2} -1]}{16}\\\\\to h'(\frac{pi}{3}) = -\frac{(2+\sqrt{3})}{32}](/tpl/images/0441/3877/da644.png)
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Suppose that f(pi/3)=4 and f'(pi/3)=-2 let g(x)=f(x)sinx and h(x)=cosx/f(x). find g'(pi/3) and h'(pi...
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