The equation of line xy is (y-3)= -2/3(x-4).what is the slope of a line perpendicular to xy?

a) -2

b) 3

c) -2/3

d) 2/3

will be the slope of the line perpendicular to xy.

Step-by-step explanation:

The equation of line xy is ( y-3 ) = (x-4)

y = ( x-4 ) + 3

y = x + + 3

y = x +

So the line has slope = and y-intercept = .

Let m is the slope of a line perpendicular to line xy.

We know that for perpendicular lines having slopes m₁ and m₂

m₁ × m₂ = -1

Therefore, for m₁ = m and m₂ =

mx () = -1

m = ()

will be the slope of the line perpendicular to xy.

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )