On trig question?
fill in the blank. if necessary, use the slash mark ( / ) for a fraction bar.
if cosθ = 3/5 , then tanθ =

Say theta=β for the sake of this problem. There isn't a theta sign I can use on .

cosβ=A/H=3/5

So the adjacent side of the right angled triangle is 3 and the hypotenuse of the right angled triangle is 5. Let's find its opposite side as tanβ=(sinβ)/(cosβ) and sinβ=O/H.

3²+Opposite²=5²

9+Opposite²=25

Opposite²=25-9

Opposite²=16

Opposite=√16=4



With this knowledge we can say that:

sinβ=O/H=4/5

Therefore:

tanβ=(4/5)/(3/5)

=(4/5) * (5/3)

=20/15

=4/3



tanβ=4/3

I’m sorry i can’t u