Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial function. f(x) = 3(4)^(2x-4)h(x) = (x + 2)^3 + 1

For x < -3 or 3.438 > 3 the exponential function exceeds the polynomial function.

Step-by-step explanation:

The given functions are

In the given functions f(x) is an exponential function and h(x) is polynomial.

We need to find the x-value in which the exponential function exceeds the polynomial function.

The table of values is shown below,

x            f(x)                    h(x)

-4        1.8×10⁻⁷              -7                   f(x)>h(x)

-3            0                      0                   f(x)=h(x)

-2         4.6×10⁻⁵             1                    f(x)<h(x)

0          0.0012                9                   f(x)<h(x)

2              3                     65                 f(x)<h(x)

3.438       161.845          161.845           f(x)=h(x)

4             768                 217                 h(x)>f(x)

From the above table it is clear that for x < -3 or 3.438 > 3 the exponential function exceeds the polynomial function.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: