Aright triangle has a hypotenuse of 25 feet and a leg of 7 feet. which of these is the length of the other leg?

A^2 + b^2 = c^2...where a and b are ur legs and c is ur hypotenuse

7^2 + b^2 = 25^2
49 + b^2 = 625
b^2 = 625 - 49
b^2 = 576...take square root of both sides, eliminating the ^2
b = sq rt 576
b = 24 ft <=== length of the other leg

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12