How do you begin to solve x^3-3x^2 > x-3?

For any polynomial, first check to see if it factors. Then you can set each factor equal to zero.


The three zeros are -1,1,3

Next plug in values in each interval between zeros to test whether its greater than 0.

Try x values: -2,0,2,4

x = -2 yields a negative result, the interval x< -1 is Not a solution.

x = 0 yields a positive result, the interval -1
x = 2 yields a negative result, the interval 1
x = 4 yields a positive result, the interval x>3 IS a solution

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