What is the 6th term of the geometric sequence where a1 = 128 and a3=8?

explicit formula:
a_n(r)^n-1

can you explain step-by-step to me how to find this?

The 6th term of the sequence is 0.125.

Step-by-step explanation:

Given : Geometric Sequence where and

To find : The 6th term.

Solution :

The formula of nth term of geometric sequence is

 ........[1]

We have given,

To find ratio we put n=3 in [1]

Now, we know first term and common ratio

Put n=6 in [1] to get 6th term of the sequence is

Therefore, The 6th term of the sequence is 0.125.

2

ok

step-by-step explanation: