∠abd is formed by a tangent and a secant intersecting outside of a circle. if minor arc ac = 72° and minor arc cd = 132°, what is the measure of ∠abd?

measure of ∠ABD = 42°

Step-by-step explanation:

Angle Formed by Tangent and Secant = (1/2)*(difference of Intercepted Arcs)

In this case the intercepted arcs are: minor arc AC and minor arc AD. Let´s first find minor arc AD, we know that:

minor arc AC + minor arc CD + minor arc AD = 360°

Then,

minor arc AD = 360° - minor arc AC - minor arc CD

minor arc AD = 360° - 72° - 132°

minor arc AD = 156°

Replacing in the aforementioned formula:

Angle Formed by Tangent and Secant = (1/2)*(difference of Intercepted Arcs)

∠ABD = (1/2)*(minor arc AD - minor arc AC)

∠ABD = (1/2)*(156° - 72°)

∠ABD = 42°

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

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step-by-step explanation: