Identify the translation rule on a coordinate plane that verifies that square a(-4,3), b(-4,8), c(-9,3), d(-9,8) and square a'(-3,4), b'(-3,9), c'(-8,4), d'(-8,9) are congruent.

a)
(x, y) → (x - 1, y - 1)

b)
(x, y) → (x - 1, y + 1)

c)
(x, y) → (x + 1, y + 1)

d)
the squares are not congruent

The translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

We are given the vertices of a square A(-4,3), B(-4,8), C(-9,3), D(-9,8) and square A'(-3,4), B'(-3,9), C'(-8,4), D'(-8,9) .

We have to find the  translation rule on a coordinate plane that verifies that square ABCD is congruent to square A'B'C'D'.

Since, the two squares o be congruent every vertex must be translated by the same rule.

So, the rule is:

(x, y) → (x + 1, y + 1)

since,

A(-4,3) → A'(-4+1,3+1)=A'(-3,4)

B(-4,8) →B'(-4+1,8+1)=(-3,9)

C(-9,3) → C'(-9+1,3+1)=(-8,4)

and D(-9,8) → D'(-9+1,8+1)=(-8,9)

Hence, the translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92