At 9: 00 on saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. the bicyclist heading north is riding 6 km/hour faster than the bicyclist heading south. at 10: 15, they are 42.5 km apart. find the two bicyclists’ rates.

the speed of the bicyclist heading south 14

the speed of the bicyclist heading north  20

Step-by-step explanation:

Let x is the speed of the bicyclist heading south

Let x+6 is the speed of the bicyclist heading north

Because, they are heading in opposite directions, so the relative speed is:

x + x + 6 = 2x+6

As we know:

<=>

<=> 170 = 10x + 30

<=> x = 14 km/hour

=> Speed of bicyclist heading north would be 14+6=20 km/hr

Hope it will find you well.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11