The table shows hunter's checking account activity for several weeks. hunter's beginning balance was $814. what was his ending balance? three column table titled hunters account. data. in the first column is date, aug. 14, aug. 20, aug. 24, aug. 30, and sept. 8. data in the second column is deposit, blank, 150, 75, blank, and blank. data in the third column is withdrawal, minus45, blank, blank, minus120, and minus250. a. $225 b. $399 c. $624 d. $1039

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

theres no picture: /

step-by-step explanation: