The equation for the circle is:
x^2+y^2−12x+6y−19=0x2+y2−12x+6y−19= 0 .
what is the center of the circle?

(-6, 3)
(12, -6)
(6, -3)

(-12, 6)

Option (c) is correct.

Center of circle is at (6, -3)

Step-by-step explanation:

Given : The equation of circle is

We have to find the center of given circle and choose from the given options.

The standard equation of circle with center (h,k) and radius r is written as  

Consider the given equation

Adding 19 both side, we have,

Group x and y terms together, we have,

Add both side 36 to make x a perfect square term,

Using identity , we have,

Similarly, for y , adding 9 both side,

rewriting in standard form , we have,

Thus, Center of circle is at (6, -3)

Option (c) is correct.

26

step-by-step explanation: