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Mathematics, 03.02.2020 14:54 kaadenday3629

The equation for the circle is:
x^2 + y^2 - 12x + 6y - 19 = 0

what is the center of the circle?

a. (-6, 3)
b. (12, -6)
c. (6, -3)
d. (-12, 6)

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Answers: 3

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The equation for the circle is:
x^2 + y^2 - 12x + 6y - 19 = 0

what is the center...
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