The prism has a surface area of 1312 mm2.
what would the surface area of the prism be if each dimension were halved?
mm2

So each dimention is 32 by 8 by 10
so the surface area=2 times(8 times 10)+(2 times (32 times 10))+(2 times (8 times 32))=2 times 80+2 times 320+2 times 256=1312

if halved
just divide each by 2
(2 times 4 times 5)+(2 times 16 times 5)+(2 times 4 times 16)=(2 times 20)+(2 times 80)+(2 times 64)=40+160+128=328
the new surface area is 328 mm^2

If you divide 0.1 and 0.6 you wii get 0.166666 which rounds to .167 which is answer b