How do you factor this quadratic?
6x^2 + x - 2

Break expression into groups such as for formula ax^2+bx+c, find u and v such that u*v=a*c and u+v=b. In this problem, next step is (6x^2-3x)+ (4x-2). Now factor out 3x from (6x^2-3x)= 3x(2x-1). Now factor out 2 from (4x-2)= 2 (2x-1).
Now you have 3x (2x-1) +2 (2x-1) so factor out common term of (2x-1).Thus, the final answer is (3x+2)(2x-1).

It creates dogx^2 and then flip your answer and multiply by 2