Abasket contains 11 apples, of which two are rotten. a sample of three apples is selected at random. in how many ways can two rotten apples be chosen?

The ways the two rotten apple be selected in taking 3 apples from the bag, can be solve using fundamental counting principles.
P = 2 x 1 x 9
P = 18 ways
the first digit is 2 because there are 2 rotten apples. then next is 1 because only 1 apples is now left after you pick the first rotten apple. then next is 9 because there no rotten apple left and 9 apples were left

Bis the right answer