The equation y−5=-2(x−3) is in point-slope form. which shows this equation in slope-intercept form?

The easiest way to do this is by graphing the equation. I'll do it:

We see that the y intercept is 11.

Formula for slope-intercept: y = mx + b

mx = slope

b = y-intercept

Now we have y = mx + 11. What's mx? We can find that out from the graph.

Let's find two points: (0,11) (4,3)

Using (y2 - y1)/x2 - x1): We see that the slope is -2.

Now we finish the slope-intercept form and plug it all in:

y =  -2x + 11