Bob has 3bookshelfs that hold a total of 27 books. he adds a fourth shelf and now has 36books. if he adds 2 more shelves, how many books can he have in total

Bob will have a total of 54 books

Step-by-step explanation:

Step 1: Determine number of books per shelf

Using the expression below;

T=b×n

where;

T=total number of books

b=number of books per shelf

n=number of book shelf

In our case;

T=27 books

b=unknown

n=3

replacing;

27=b×3

3 b=27

b=27/3

b=9

Consider, when T=36, and n=4

36=b×4

b=36/4

b=9 books per shelf

It is determined that a shelf holds a standard of 9 books

Step 2: Total number of books

Using the expression;

T=b×n

where;

b=9 books per shelf

n=(4+2)=6 shelf

replacing;

T=(9×6)=54 books

Bob will have a total of 54 books

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )