According to the fundamental theorem of algebra, the graph of f(x) = x^2 - 4x + 3, has roots. from the graph we can see that it has zeros.

According to the Fundamental Theorem of Algebra, the graph of f(x) = x^2 - 4x + 3, has 2 roots. From the graph we can see that it has two real zeros

Step-by-step explanation:

Part 1)

we have

Is a polynomial of degree 2

According to the Fundamental Theorem of Algebra, any polynomial of degree n has n roots

so

The polynomial has 2 roots.

Part 2)

we know that

A "root" (or "zero") is where the polynomial is equal to zero

From the graph we can see that the polynomial is zero at x=-3 and x=-1

therefore

The function has two real zeros

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

b. x + 1

step-by-step explanation:

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