128 pts

high school mathematics 5+3 pts

the general equation for depreciation is given by y = a(1 – r)t, where y = current value, a = original cost, r = rate of depreciation, and t = time, in years. a car was purchased 6 years ago for $25,000. if the annual depreciation rate is 11%, which equation can be used to determine the approximate current value of the car?
a. 25,000(0.89)^6 b.(25,000 x 0.11)^6 "answers should look something like this."

i think is g(1)=-1.

hope that i can

20

step-by-step explanation:

assuming you meant there are 24 pounds of apples in each case, if this is not what you meant, correct me so i can you further

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5