Write an equation for the line that is parallel to the given line and that passes through the given point. y = �5x 3; (�6, 3

I am assuming y= –5x+3  and the point is (–6, 3). If not, just leave out the negative signs.

The general formula for a line is y=mx+c. Where m=slope, c= some constant. 

Parallelism mean equal slopes. So the slope of the line will be the coefficient of the x term in y= –5x+3.

So we have, y=-5x+c

To find c, substitute values from the given point, (x=-6, y=3) and solve.

c= 3 + 5(-6)
c=-27

Therefore y= –5x–27