If f(x) = 2x3 - 4x2 + 2, and g(x) = x3 - 2x2 - 2x + 4, then f(x) - g(x) =

f(x) - g(x) = x³ - 2x² + 2x -2.

Step-by-step explanation:

Given : f(x) = 2x³ - 4x² + 2 and g(x) = x³ - 2x² - 2x + 4.

To find  :  f(x) - g(x) .

Solution : We have  f(x) = 2x³ - 4x² + 2 and g(x) = x³ - 2x² - 2x + 4.

f(x) - g(x) =  2x³ - 4x² + 2 - (  x³ - 2x² - 2x + 4).

f(x) - g(x) =  2x³ - 4x² + 2 -  x³ + 2x² + 2x -4.

Combine like terms

f(x) - g(x) = 2x³ - x³ - 4x² + 2x² +2x + 2 -4.

f(x) - g(x) = x³ - 2x² + 2x -2.

Therefore, f(x) - g(x) = x³ - 2x² + 2x -2.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)