Solve the system below
y=x^2-2x-6
y=4x+10

a. (-2,2)
b. (8,42)
c. (-2,,42)
d. no real solution

solve the system below
y=x^2 -4
y= -4

a. (0,-4)
b. (-4,0)
c. (0,-,0)
d. no real solution

For the system y=x^2-2x-6 & y=4x+10 the answer is A. (-2,2)
y=-2^2-2(-2)-6
y=4+4-6
y=8-6
y=2
y=4x+10
y=4 (-2)+10
y=-8+10
y=2

For the system y=x^2-4 & y=-4 the answer is
A.(0,-4)
y=0^2-4
y=-&
For the system

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