The circle shown below has ab and bc as its tangents: ab and bc are two tangents to a circle which intersect outside the circle at a point b. if the measure of arc ac is 130°, what is the measure of angle abc? (1 point) 55° 50° 60° 65°

he picture in the attached figure

we know that

The measure of the external angle is the semidifference of the arcs that it covers.

so

the arcs that it covers are

arc AC and arc ABC

We have

AB and BC as its tangents

the measure of arc AC is °

In addition, a circle has degrees by definition

so

°= arc AC + arc ABC

°= ° + arc ABC

arc ABC= °- °= °

Then

Angle ABC =

Angle ABC= °

therefore

the answer is

Angle ABC= °

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

idk

step-by-step explanation: