If g(x) =1/x were shifted 2 units to the left and 2 units up, what would the new equation be? a. g(x)=1/x-4 b. g(x)=1/(x-2)+2 c. g(x)=1/(x+2)+2 d. g(x)=1/x+4

New equation would be G(x) =  .

Step-by-step explanation:

Given : G(x)= were shifted 2 units to the left and 2 units up,

To find : what would the new equation be.

Solution : We have given that G(x)= .

By the transformation rule : graph of f(x) would shifted left by h unit when f(x+2) and shifted up k unit if f(x) +k.

Then G(x) =  .

Therefore, New equation would be G(x) =  .

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: