What are two consecutive odd integers whose product is 99.

Consecutive odd integers are 2 apart

they 2 numbers are
n and n+2

their product is 99

n times n+2=99
n(n+2)=99
n²+2n=99
minus 99 both sides
n²+2n-99=0
what 2 numbres multiply to -99 and add to get 2
if you can't do that
complete square
n²+2n+1-100=0
(n+1)²-100=0
(n+1)²=100
sqrt both sides
n+1=+/-10
n=-1+/-10
n=-11 or 9

if n=-11, then n+2=-9
if n=9 then n+2=11

the integers are -11 and -9 or  9 and 11

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With a continuous thought process.