If the nth term is 299find the value of n while arthmetic sequence is 13,24,35..

Aritmetic
an=a1+d(n-1)
a1=first term
d=common differnce

common differnce is a term minus pervious term
24-13=11
d=11
a1=first term=13

13+11(n-1)
the nth term
299=13+11(n-1)
solve
distribute
299=13+11n-11
299=11n+2
minus 2 both sides
297=11n
divide both sides by 11
27=n
it is the 27th term

Y’all got to do it all over