Eight oranges were selected at random from a crate of 53 oranges. their diameters were measured, in millimeters, and then recorded. diameters: 45, 46, 42, 53, 60, 49, 54, 51 what is the estimated mean diameter of the 53 oranges in the crate? enter your answer in the box.

Estimated mean diameter of the 53 oranges = 50mm

Step-by-step explanation:

To find the estimated mean diameter one would find the mean of the selected sample of the total population

Since the 8 samples are selected at random from a population of 53 oranges

Estimated mean diameter = (45+46+42+53+60+49+54+51)/8

= 400/8

= 50mm

Estimated mean diameter of the 53 oranges = 50mm

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amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: