The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. what is the general form of the equation for the circle?
a- x2 + y2 − 6x − 16y + 48 = 0
b- x2 + y2 − 6x − 16y − 25 = 0
c- x2 + y2 + 6x + 16y + 48 = 0
d- x2 + y2 + 6x + 16y − 25 = 0

The answer is A. To understand that, you need to put it in order by the x's and the y's to get x^2-6x + y^2-16y = -48. Now complete the square on both the x and the y terms to get (x^2-6x+9) +(y^2-16y+64) = -48+9+64. Rewriting that in vertex form on the left and doing the math on the right gives you
(x-3)^2 + (y-8)^2 = 25, which shows you a center of (3,8) and a radius of 5.

You shouldn’t be using this website cheater

Idon't take stuff like this new to me