An object is thrown off a 256-foot-tall building, and the distance of the object from the ground is measured every second. the function that models the height, h, of the object after t seconds is h(t) = –16t2 + 96t + 256. determine the time when the object hits the ground. after how many seconds does the object hit the ground? a.2 b.4 c. 8 d. 16

C. 8

Step-by-step explanation:

When the object hits the ground, h(t) = –16t^2 + 96*t + 256 = 0. Using the quadratic formula (where a= -16, b=96 and c=256) we get:  

The first root (-2) has no physical sense and is discarded. Then, the object hits the ground after 8 seconds.

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step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b