Mathematics, 21.10.2019 22:40 jenesis8
Solve for x.
2x^2+7x−5=0
1.) x= 2/(−7±√89)
2.) x=4/(−7±√3)
3.) x= 4/(−7±√89)
4.) x= 2/(−7±√3)
Answers: 2
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Solve for x.
2x^2+7x−5=0
1.) x= 2/(−7±√89)
2.) x=4/(−7±√3)
...
2x^2+7x−5=0
1.) x= 2/(−7±√89)
2.) x=4/(−7±√3)
...
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