This is 70 points i will report anyone who answers wrong just for points! i will be asking two questions answer correctly or i will report you : )

question 1 : (x+3)y=14 which ordered pair in the form (x, y) is a solution of this equation
(11, 1)
(3, 2)
(5, 2 ) (7, 2)

second question: which pairs are solutions to the equation
5xy+9=44

1, 7 and 4, 11
1, 7 and 7, 1
7,1 and 2, 3
4, 11 and 2, 3

QUESTION 1: In these type of question, the easiest way to get the answer is try to plug in the x and y values from the options given in the equation given, So in the first question all the choice except C are more then 14 if you plug in x and y's, for eg, if you plug in x = 3 and y = 2 , you get (3+3)2 = 14 6 x 2 = 14 12 is not equal to 14, so this eliminates this choice but if you chose C you get, (11+3)1 = 14 14 = 14 so this makes C the solution for first question and for the second question do the same thing, and the answer will be D. Hope this helps

QUESTION 2: 5xy + 9 = 44

5xy = 35

xy = 7

solution pairs are:

C. (1, 7) and (7, 1)

not mentioned: (-1.-7) and (-7, -1)

Hope this helps

Plzz don't forget to rate and thanks me

Letter a i would say