7-107. identify the terms, coefficients, constant terms, and factors in each expression below.
a. 3x2 + (−4x) + 1
b. 3(2x − 1) + 2

a. Terms:

Coefficients: 3, -4

Constant terms: 1

Factors: (3x -1) and (x -1)

b. Terms: 6x, -1

Coefficients: 6

Constant terms: -1

Factors: No factors

Step-by-step explanation:

The given expressions are:

a.

b. 3(2x -1) + 2

Let's take the first expression

can be written as because +(-4x) = -4x

Terms:

Coefficients: 3, -4

Constant terms: 1

Factors:

=

So, the factors are (3x -1) and (x -1)

Let's take second expression.

3(2x -1) + 2

Let's simplify this. Using the distributive property a(b -c) = ab - ac

3(2x -1) + 2  = 3(2x) +3(-1) + 2

= 6x - 3 + 2

= 6x -1

Terms: 6x, -1

Coefficients: 6

Constant terms: -1

Factors:

No factors

step-by-step explanation:

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.