Mathematics, 19.10.2019 14:00 katietinary1657

Its almost midnight and im taking my benchmarks

girls boys
10 8
12 6
9 4
15 5
25 10
8 15
6 7
14 8
18 12
11 11
9 9
13 5
15 4

jeffrey surveys the 13 girls and 13 boys in his class to find out how many pairs of shoes they have in their closets. which statement is true?
a) the value of q3 for the boys is greater than the value of q3 for the girls.
b) the mean number of shoes for the boys is greater than the mean number of shoes for the girls.
c) the median number of shoes for the girls is greater than the median number of shoes for the boys.
d) the median number of shoes for the boys is greater than the median number of shoes for the girls.

Answers: 2

Show answers

Answers

Answer from: hayden6920

The median number of shoes for the girls is greater than the median number of shoes for the boys.

Step-by-step explanation:

Jeffrey surveys the 13 girls and 13 boys in his class to find out how many pairs of shoes they have in their closets

Girls Data :10, 12, 9 , 15, 25,8, 6,14, 18 , 11 , 9 , 13 , 15

Arrange the data in the ascending order :

6,8,9,9,10,11,12,13,14,15,15,18,25

No. of observations n = 13(odd)

So, Median = $(\frac{n+1}{2})^{\text{th term}}$

= $(\frac{13+1}{2})^{\text{th term}}$

= $(\frac{14}{2})^{\text{th term}}$

= $(7)^{\text{th term}}$

Thus the median of the girls data is 12.

Now to find Q_3

Consider the set of values right to the median .

13,14,15,15,18,25

Now find the median of this data

No. of observations n = 6(even)

Median = $\frac{(\frac{n}{2}+1)^{\text{th term}}+\frac{n}{2}^{\text{th term}}}{2}$

So, Median = $\frac{(\frac{6}{2}+1)^{\text{th term}}+\frac{6}{2}^{\text{th term}}}{2}$

Median = $\frac{4^{\text{th term}}+3^{\text{rd term}}}{2}$

Median = $\frac{15+15}{2}$

Median =

Mean = $\frac{\text{Sum of all observations }}{\text{number of observations}}$

Mean = $\frac{10+12+ 9 +15+25+8+6+14+18+ 11 +9+ 13+15}{13}$

Mean = 12.69

So, Q_3 for girls is 15 and median is 12 and mean is 12.6.

Boys data : 8,6,4,5,10,15,7,8,12,11,9,5,4

Arrange the data in the ascending order :

4,4,5,5,6,7,8,8,9,10,11,12,15

No. of observations n = 13(odd)

So, Median = $(\frac{n+1}{2})^{\text{th term}}$

= $(\frac{13+1}{2})^{\text{th term}}$

= $(\frac{14}{2})^{\text{th term}}$

= $(7)^{\text{th term}}$

Thus the median of the boys data is 8

Now to find Q_3

Consider the set of values right to the median .

8,9,10,11,12,15

Now find the median of this data

No. of observations n = 6(even)

Median = $\frac{(\frac{n}{2}+1)^{\text{th term}}+\frac{n}{2}^{\text{th term}}}{2}$

So, Median = $\frac{(\frac{6}{2}+1)^{\text{th term}}+\frac{6}{2}^{\text{th term}}}{2}$

Median = $\frac{4^{\text{th term}}+3^{\text{rd term}}}{2}$

Median = $\frac{11+10}{2}$

Median = 10.5

Mean = $\frac{\text{Sum of all observations }}{\text{number of observations}}$

Mean = $\frac{4+4+5+5+6+7+8+8+9+10+11+12+15}{13}$

Mean =

So, Q_3 for boys is 10.3 and median is 8 and mean is 8

Since we can see that the value of Q_3 , mean and median opf girls is greater than boys.

So, Option C is correct.

The median number of shoes for the girls is greater than the median number of shoes for the boys.

Answer from: Quest

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2

Answer from: Quest

answer: sherk

step-by-step explanation:

just give up and watch the best anime ever sherk

Tell whether the table of values represents a linear function and exponential function or a quadrati

Another question on Mathematics

Mathematics, 21.06.2019 15:00

The image of the point (-6, -2)under a translation is (−7,0). find the coordinates of the image of the point (7,0) under the same translation.

Answers: 1

Answer

Mathematics, 21.06.2019 18:00

Lydia collected two sets of data one set of data shows an outlier. which set has an outlier, and which number is the outlier?

Answers: 2

Answer

Mathematics, 21.06.2019 19:30

Si la base de un triángulo isósceles mide 70 m y el ángulo opuesto a ésta mide 58°; entonces ¿cuánto mide la altura de dicho triángulo? a) 21.87 m. b) 40.01 m. c) 43.74 m. d) 63.14 m.

Answers: 1

Answer

Mathematics, 21.06.2019 22:00

Worth 100 points need the answers asap first row -x^2 2x^2 (x/2)^2 x^2 x is less than 2 x is greater than 2 x is less than or equal to 2 x is greater than or equal to 2 second row -5 -5/2 4 5 •2 is less than x& x is less than 4 •2 is less than or equal to x & x is less than or equal to 4 •2 is less than or equal to x& x is less than 4 •2 is less than x& x is less than or equal to 4

Answers: 2

Answer

You know the right answer?

Its almost midnight and im taking my benchmarks

girls boys
10 8
12 6
...

Questions