What is the equation of the line that passes through (4,0) and (6,-8)?

Hello : let  A(4,0)    B(6,-8)
the slope is :   (YB - YA)/(XB -XA)
(-8-0)/(6-4)  = -4
an equation is : y=ax+b     a is a slope

y = -4x +b

the line through point  (4,0) : 0 = -4(4)+b
b = 16
the equation is : y =-4x+16

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

salary

step-by-step explanation: