What is 3(k-6)=15? provide an explanation.

I might be able to give you a hand here!

First you would have use the distributive property to make this an easier problem.So take 3 times k (if the variable has no number just add a one) and 3 times -6 to get the problem of 3k-18=15. Now you would add 18 to -18 and get 0 and do it on the 15. 15+18=33,now you have 3k=33.now you divide 3/3 and get 1 and divide 33 by 3 to get 11.
Answer is k=11

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.