There are 16 games played in a regular season of football. the dallas cowboys win the first game of the season. they then lose the next two games, followed by a six win streak. what is the probability that the dallas cowboys will win game 11 of the football season?

Since there are 16 games, I will make 16 slots

| ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? |

I will use W for a win and L for a Loss.

| W | L | L | W | W | W | W | W | W | ? | ? | ? | ? | ? | ? | ? |

However, this is a trick question!

The information given is irrelevant.

There is a 50 50 chance of any team winning any game

So there is a 50% probability that they will win game 11.

Hope that helps!

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: