Find exact values for sin θ, cos θ and tan θ if sec θ = 2 and θ terminates in quadrant i
what do i do in this situation where it gives a value that is not a fraction? and what are the exact values for sin and cos based off of this? provide an explanation.

If the secant theta is 2, then the cosine theta is 1/2. In the first quadrant, with cosine is side adjacent over hypotenuse, then the angle in question is a 60 degree angle. The side opposite the angle is sqrt3. The sin of a 60 degree angle is sqrt3/2 and the tangent is the side opposite over the side adjacent which is sqrt3/1 or just sqrt3.

(m+11n)^2=(m+11n)(m+11n)=m^2+11mn+11mn+121n^2=m^2+22mn×121n^2 for example; use foil: (a+b)(a+b)first. a^2outside. abinside. ablast. b^2