Write an equation of the line that has a slope of 3 and contains the point (4,9) in point-slope form

Y-y=m(x-x)

y-9=3(x-4)

Hey how's it going.

So you want to find an equation of slope 3 and passing through the point (4,9). You have to know first the general form of an equation which is: y = ax + b, where a is the slope and b is y-intercept. Now let's get started:

a=3, so the equation becomes: y = 3x + b
And you have the point (4,9) on it
So you substitute the coordinates of this point to find b. y = 9 and x = 4 :

9 = 3(4) + b
9 = 12 + b
b = 9 - 12
b = -3

So finally, the equation of slope 3 and contains the point (4,9) is:
y = 3x - 3
Hope I helped.