The point q(9, -1) is reflected across the y axis. use arrow notation to describe the original point and its reflection

a) q(9, -1) -> q'(9,1)
b) q(9, -1) -> q(-9, 1)
c) q(9 -1) -> q(-9, -1)
d) q(9 -1) -> q(9, -1)

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10