The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = . what is the value of b?

the correct answer is -9

The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = . What is the value of b?

⇒ -9

i just took the test

b =-9

Step-by-step explanation:

Given is an equation of a parabola

This is a parabola open up

Axis of symmetry is given as x = 3/2

Hence parabola would have equation of the form

Compare this with the given equation

Equate the coefficient of x square to get

a =3

Equate coefficient of x to get

-3a = b

Or b=-3(3) = -9

Hence value of b =-9

slope =   (y2 -y1) ÷ (x2 -x1)

slope = (0 -0) / (-5, -7)

slope = 0 / -12 = 0

the slope of the line is zero.   it is perfectly horizontal.

step-by-step explanation:

i think the answer is c sorry if it's wrong