The function, f(x) = –2x2 + x + 5, is in standard form. the quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c = 5. the discriminate b2 – 4ac is 41. now, complete step 5 to solve for the zeros of the quadratic function. 5. solve using the quadratic formula. x = what are the zeros of the function f(x) = x + 5 – 2x2? x = x = x = x =

A quadratic equation   ....[1] where, a, b and c are coefficient then;

the solution fore this equation we have;

        ....[2]

Given the function in the standard form:

The quadratic equation is:

On comparing with equation [1] we have;

a = -2 , b = 1 and c = 5.

The discriminant is given by:

then;

Solve for the zeros of the quadratic function:

Substitute the given values in [1] we have;

then;

and

⇒ and

Therefore, the zeros of the given  function are:

,

translate k to n and reflect across the line containing jk.

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.